✅ Output Revealed ! Did you predict the output correctly? 👀 Actual Output: ban 💡 Explanation: This code removes duplicate characters while preserving the order of their first appearance. The string starts as "banana". result is an empty list. Each character is checked: 'b' → added ✅ 'a' → added ✅ 'n' → added ✅ Remaining 'a', 'n', 'a' are skipped because they're already in result. Finally, "".join(result) combines ['b', 'a', 'n'] into the string "ban". 🎯 Final Output: ban 🚀 Key Takeaway This is a simple and effective way to remove duplicate characters while maintaining their original order. It also demonstrates how lists can be used to keep track of values that have already been seen. 💬 Did you guess ban? Comment "Got it!" if you were right, or share what you guessed before seeing the answer.

✅ Output Revealed! Did the "isalpha()" + "isdigit()" trick you? 👀 Actual Output: 21 💡 Explanation: The condition checks "word.isalpha()" OR "ch.isdigit()". - ""dhoni07"" → only the 2 digits ("0", "7") satisfy the condition → count decreases by 2. - ""virat18"" → only the 2 digits ("1", "8") satisfy the condition → count decreases by 2. - ""Rohit"" → the entire word is alphabetic → all 5 characters satisfy the condition → count decreases by 5. So the total becomes: 30 − 2 − 2 − 5 = 21 🎯 Final Output: 21 🚀 Key Takeaway Even though "word.isalpha()" is checked inside the inner loop, it evaluates the entire word, not the individual character. For the first two words, only digits trigger the condition, while every character in ""Rohit"" triggers it. 💬 Did you predict 21? Comment "Got it!" if you were right, or share your guess before seeing the answer!

✅ Output Revealed – Code15! Did the nested loop trick you? 👀 Actual Output: 15 💡 Explanation: The important part is: if word.count("a") == 1: count += word.count("a") Every word contains exactly one "a": "apple" → 1 a → inner loop runs 5 times → +5 "ant" → 1 a → inner loop runs 3 times → +3 "bat" → 1 a → inner loop runs 3 times → +3 "ball" → 1 a → inner loop runs 4 times → +4 So: 5 + 3 + 3 + 4 = 15 🎯 Final Output: 15 🚀 Key Takeaway Even though word.count("a") is checked inside the inner loop, it checks the entire word every time. Since each word has exactly one "a", 1 is added once for every character in that word. 💬 Did you predict 15? Comment "Got it!" if you were right!